Answer:

(5,10)(2,7)

Rise/run = 10-7/5-2 = 3/3 = 1

Therefore, the slope of the line is 1.

Answer:
My answer was right I looked it up why you delete it?!

What is four and fifteen thousandths using base ten numerials

Can someone help me with this.In a school, 30% of the students have hazel eyes. Find the experimental probability that in a group of 4 students, at least one of them has hazel eyes. The problem has been simulated by generating random numbers. The digits 0-9 were used. Let the numbers "6". "7", and "8" represent the 30% of students with hazel eyes. A sample of 20 random numbers is shown.

The number in the blanks represents

The base of a square pyramid has a side length of 6 inches. The height of the pyramid is 12 inches. What is the volume of the pyramid? A. 108 in3 B. 36 in3 C. 72 in3 D. 144 in3

Donna is planning a vacation. She looks at a map with the following scale. 12 inch=15 miles On the map, Donna finds the distance from Richmond, VA to Pittsburgh, PA is 13 inches and the distance from Pittsburgh, PA to Boston, MA is 19 inches. If she drives from Richmond to Pittsburgh then to Boston, about how many miles will she travel?

Can someone help me with this.In a school, 30% of the students have hazel eyes. Find the experimental probability that in a group of 4 students, at least one of them has hazel eyes. The problem has been simulated by generating random numbers. The digits 0-9 were used. Let the numbers "6". "7", and "8" represent the 30% of students with hazel eyes. A sample of 20 random numbers is shown.

The number in the blanks represents

The base of a square pyramid has a side length of 6 inches. The height of the pyramid is 12 inches. What is the volume of the pyramid? A. 108 in3 B. 36 in3 C. 72 in3 D. 144 in3

Donna is planning a vacation. She looks at a map with the following scale. 12 inch=15 miles On the map, Donna finds the distance from Richmond, VA to Pittsburgh, PA is 13 inches and the distance from Pittsburgh, PA to Boston, MA is 19 inches. If she drives from Richmond to Pittsburgh then to Boston, about how many miles will she travel?

Step 1: 0.135 = 135/ 1000

Step 2: simplify 135/1000 = 27/200

Step 2: simplify 135/1000 = 27/200

**Answer:**

Number of **Large** Pizzas: **30**

Number of **Medium** Pizzas:** 8**

Number of **Small** Pizzas:** 27**

**Step-by-step explanation:**

L = # of large Pizzas

M = # of medium Pizzas

S = # of small Pizzas

Amount:

L = 4M - 2

S = 3M + 3

Cost:

21L + (I'm assuming you meant 14) 14M + 7S = 931

Plus in the Amounts to the Cost:

21(4M - 2) + 14M + 7(3M + 3) = 931

84M - 42 + 14M + 21M +21 = 931

Combine like terms:

119M - 21 = 931

Isolate the Variable:

119M - 21 + 21 = 931 + 21

119M = 952

119M/119 = 952/119

**M = 8**

Plug it into the Amount equations:

Large: L = 4(8) - 2

L = 32 - 2

**L = 30**

Small: S = 3M + 3

S = 3(8) + 3

S = 24 + 3

**S = 27**

Check your work (plug the values into Cost.):

21(30) + 14(8) + 7(27) = 931

630 + 112 + 189 = 931

931 = 931

The number of medium pizzas ordered was 10. Hence, based on the given relationships, the number of large pizzas was 38 and the number of small pizzas was 33.

To solve this problem, really, we are using three algebraic expressions that represent the total cost, the relationship between the large and medium pizzas, and the relationship between the small and medium pizzas.

We can define **M** as the number of medium pizzas, **L** as the number of large pizzas, and **S** as the number of small pizzas. We can then set up the following equations based on the problem:

- $21L + $14M + $7S = $931
- L = 4M - 2
- S = 3M + 3

We can substitute equations 2 and 3 into equation 1 to get a single equation in terms of M:

**$21(4M-2) + $14M + $7(3M+3) = $931**

Which simplifies to:

93M = 931

Then,** M=10, hence, the number of medium pizzas is 10, number of large pizzas (4M-2) is 38, and the number of small pizzas (3M+3) is 33.**

#SPJ2

Well, if you bought 10, it would be $2, but due to the decreasage, if you bought 8 it would be $2. The prrcantage decrease should be 20%.

2.1, 2.2, 2.3, or 2.4. Any of those should work

tens = 10

56 x 10 = 560

56 x 10 = 560

56 tens

=56+56+56+56+56+56+56+56+56+56

= 56 x 10

=560

Solutions

75: 3 5 5

90: 2 3 3 5

GCF: 3 * 5

= 15

75: 3 5 5

90: 2 3 3 5

GCF: 3 * 5

= 15