- 1

- m - 7 = 5

3

Answer:

1/3m-7=5

One solution was found :

m = 36

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

1/3*m-7-(5)=0

Step by step solution :

Step 1 :

1

Simplify —

3

Equation at the end of step 1 :

1

((— • m) - 7) - 5 = 0

3

Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

7 7 • 3

7 = — = —————

1 3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

m - (7 • 3) m - 21

——————————— = ——————

3 3

Equation at the end of step 2 :

(m - 21)

———————— - 5 = 0

3

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

5 5 • 3

5 = — = —————

1 3

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

(m-21) - (5 • 3) m - 36

———————————————— = ——————

3 3

Equation at the end of step 3 :

m - 36

—————— = 0

3

Step 4 :

When a fraction equals zero :

4.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

m-36

———— • 3 = 0 • 3

3

Now, on the left hand side, the 3 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

m-36 = 0

Solving a Single Variable Equation :

4.2 Solve : m-36 = 0

Add 36 to both sides of the equation :

m = 36

One solution was found :

m = 36

I happen this help

1/3m-7=5

One solution was found :

m = 36

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

1/3*m-7-(5)=0

Step by step solution :

Step 1 :

1

Simplify —

3

Equation at the end of step 1 :

1

((— • m) - 7) - 5 = 0

3

Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

7 7 • 3

7 = — = —————

1 3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

m - (7 • 3) m - 21

——————————— = ——————

3 3

Equation at the end of step 2 :

(m - 21)

———————— - 5 = 0

3

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

5 5 • 3

5 = — = —————

1 3

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

(m-21) - (5 • 3) m - 36

———————————————— = ——————

3 3

Equation at the end of step 3 :

m - 36

—————— = 0

3

Step 4 :

When a fraction equals zero :

4.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

m-36

———— • 3 = 0 • 3

3

Now, on the left hand side, the 3 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

m-36 = 0

Solving a Single Variable Equation :

4.2 Solve : m-36 = 0

Add 36 to both sides of the equation :

m = 36

One solution was found :

m = 36

I happen this help

MP of an article is $1400. Find the SP of that article in cents if the shopkeeper adds 13% VAT after allowing 45% discount. (100 cents =$1)

The value z is directly proportional to c. When z = 20, c = 10. Find an equation relating z and c. *

Suppose that instead of using natuarl logarithma to compute b, we use logarithms with the base 10 and define b=(log r)/(log 2). Does this change the value of b?

3 days after the start of an experiment there were 484 bacteria in a culture. After 5 days there were 1135. Use a system of equations to determine the initial number of bacteria in the culture (c) and the k value for the growth

Which situation is most likely to have a constant rate of change?HELP

The value z is directly proportional to c. When z = 20, c = 10. Find an equation relating z and c. *

Suppose that instead of using natuarl logarithma to compute b, we use logarithms with the base 10 and define b=(log r)/(log 2). Does this change the value of b?

3 days after the start of an experiment there were 484 bacteria in a culture. After 5 days there were 1135. Use a system of equations to determine the initial number of bacteria in the culture (c) and the k value for the growth

Which situation is most likely to have a constant rate of change?HELP

**Answer:**

$20

**Step-by-step explanation:**

It is clear that deduction will be either percent or $20 , whichever is greater

Lets evaluate 2 percent of the last bill of

Thus, $17.4 is less than $ 20

Thus, $20 will be the minimum monthly payment

2 % of 870 = $ 17.4

$ 17.4 is less than $ 20

Since the higher amount is deducted, his monthly charges would be $20.

Hope this helps! :D

$ 17.4 is less than $ 20

Since the higher amount is deducted, his monthly charges would be $20.

Hope this helps! :D

A**nswer:**

40%

**Step-by-step explanation:**

11+24+16+9=60

24/60=2/5

.40

40%

1.0000

0.8810

0.8413

0.9987

The required **probability **that a bottle has a volume greater than 992 mL is 0.84134. Option C is correct

Given that,

A bottler of drinking water fills plastic bottles with a **mean volume **of 999 milliliters (ml) and a **standard deviation **of 7 ml. The fill volumes are normally distributed. What is the **probability **that a bottle has a volume greater than 992 mL, is to be determined

**Probability **can be defined as the **ratio **of favorable **outcomes **to the total number of **events**.

We use Z-statistic to find out the probability,

z = (x − μ) / σ

x = raw score = 992 mL

μ = population mean = 999 mL

σ = standard deviation

z = [992 − 999]/7

z = -1

P-value from **Z-Table**:

P(x<992) = 0.15866

P(x>992) = 1 - P(x<992) = 0.84134

Thus, the required **probability **that a bottle has a volume **greater **than 992 mL is 0.84134

Learn more about **probability **here:

**#SPJ2**

**Answer:**

0.8413

**Step-by-step explanation:**

Find the z score.

z = (x − μ) / σ

z = (992 − 999) / 7

z = -1

Use a chart or calculator to find the probability.

P(Z > -1)

= 1 − P(Z < -1)

= 1 − 0.1587

= 0.8413

let x=gallons of 80% solution to be mixed

x+80=gallons go final 70% mixture

..

80%*x+30%*80=70%*(x+80)

.8x+24=.7x+56

.1x=32

x=320

gallons of 80% solution to be mixed=320

x+80=gallons go final 70% mixture

..

80%*x+30%*80=70%*(x+80)

.8x+24=.7x+56

.1x=32

x=320

gallons of 80% solution to be mixed=320

To obtain a mixture that is 70% **antifreeze,** you need to mix 70 gallons of an 80% antifreeze solution with 70 gallons of a 30% antifreeze solution.

To determine how many gallons of an 80% antifreeze solution must be mixed with 70 gallons of 30% antifreeze to get a mixture that is 70% antifreeze, we can use the concept of the concentration of solutions.

Let's assume x gallons of the 80% antifreeze solution need to be added.

The amount of antifreeze in the 80% solution is 0.8x gallons, and the amount of antifreeze in the 30% solution is 0.3 * 70 = 21 gallons. The total amount of antifreeze in the final mixture is 0.7 * (70 + x) gallons.

Setting up the equation: 0.8x + 21 = 0.7 * (70 + x).

Solving for x, we get x = 70 gallons. Therefore, you need to mix 70 gallons of the 80% antifreeze solution with 70 gallons of the 30% antifreeze solution to get a mixture that is 70% antifreeze.

#SPJ3

Answer:

£32 in total for the top and two trousers

Step-by-step explanation:

The price for a top In the "cloth for you" shop= £10

The price for a bermuda trouser In the "cloth for you" shop= £12

There is a 20% discount on tops

The price If I bought one top and would trouser will be

(10-(0.2*10)) for the top

2(12) for the trouser

Total= (10-(0.2*10))+ 2(12)

Total = 10-2+24

Total = £32

So I spent £32 in total for the top and two trousers

k(x) = -5x² - 125

The zeros of k are x= □ and x= □

**Answer:**

x = ±5i

**General Formulas and Concepts:**

__Pre-Alg__

- Order of Operations:
**BPEMDAS**

__Alg II__

- √-1 is imaginary number i

**Step-by-step explanation:**

__Step 1: Define function__

k(x) = -5x² - 125

__Step 2: Find roots__

- Set function equal to 0: 0 = -5x² - 125
- Factor out -5: 0 = -5(x² + 25)
- Divide both sides by -5: 0 = x² + 25
- Subtract 25 on both sides: -25 = x²
- Rewrite: x² = -25
- Square root both sides: x = ±√-25
- Rewrite: x = √-1 · ±√25
- Evaluate: x = ±5i